The insured has a PAP with single liability of $50,000. The following loss occurs: $37,000-BI pedestrian; $3,000-Display window; $10,000-Sports car; $1,500-Legal defense. How much would his policy pay for the loss?

The answer is 51,500.00 which is the total of all the losses which exceed the liability covergae by 1, 500.00 - I thought that the policy was going to pay the 50,000.00 dollars only because that is the limit of the liability -

can someone please clarify for me - thank you